Sanath Devalapurkar: Ruminations about Langlands duality with generalized coefficients
Ruminations
Let $\mathbb{k}$ be a $\mathbb{Q}$-commutative algebra, $G$ a connected reductive group over $\mathbb{C}$. Then there is derived geometric Satake equivalence $$\operatorname{Shv}_ {G(\mathbb{O})}(\mathrm{Gr}_ {G},\mathbb{k})\cong \operatorname{QCoh}(\check{\mathfrak{g}}^{\ast}_ {\mathbb{k}}[2]/\check{G}_ {\mathbb{k}})$$ and renormalized version $$\operatorname{Shv}^{\text{ren}}_ {G(\mathbb{O})}(\mathrm{Gr}_ {G},\mathbb{k})\cong \operatorname{QCoh}(\check({\mathfrak{g}}^{\ast}_ {\mathbb{k}})^{\wedge}_ {\mathcal{N}}[2]/\check{G}_ {\mathbb{k}})$$ and loop rotation version $$\operatorname{Shv}_ {G(\mathbb{O})\rtimes \mathbb{G}_ {m}^{\text{rot}}}(\mathrm{Gr}_ {G},\mathbb{k}) \cong \mathrm{U}_ {\hbar}(\check{\mathfrak{g}})\text{-Mod}$$ and renormalized version $$\operatorname{Shv}^{\text{ren}}_ {G(\mathbb{O})}(\mathrm{Gr}_ {G},\mathbb{k})\cong \operatorname{QCoh}(\check({\mathfrak{g}}^{\ast}_ {\mathbb{k}})^{\wedge}_ {\mathcal{N}}[2]/\check{G}_ {\mathbb{k}}) .$$
Now assume that $G$ is simply connected and simply laced, then $\check{G}\cong G/Z(G)$, and $\check{\mathfrak{g}}^{\ast}\cong \mathfrak{g}$. In this case, $G\twoheadrightarrow \check{G}$ acts on $\mathfrak{g}$.
Remark 1. Whittaker approach: $$\operatorname{QCoh}(0\times^{\mathbb{L}}_ {\check{\mathfrak{g}}_ {\mathbb{k}}}0)(\check{G}_ {\mathbb{k}})\hookrightarrow \operatorname{Shv}(\mathrm{Gr}_ {G},\mathbb{k}).$$
Question 2. What if $\mathbb{k}=$commutative ring spectra?
Let $X$ be a space and then one can get $C^{\ast}(X,\mathbb{Z})$ and $H^{\ast}(X,\mathbb{Z})$ via a cohomology theory. There are also generalized cohomology theories.
\begin{align} \operatorname{Spc} &\rightarrow \operatorname{GrAb} \\ \ast & \mapsto \mathbb{Z}\text{ in every even weight} \\ X &\mapsto \operatorname{KU}^{\ast}(X) \end{align} is the complex $K$-theory.
Morally, spectra linearize spaces.
where the vertical arrow is $X\mapsto C^{\ast}(X,k):=\mathrm{Maps}_ {p}(\Sigma^{\infty}X,k)$
Just as one can form $\mathrm{Shv}(X,\mathbb{Z})$, one can also form $\operatorname{Shv}(X,k)$ for any commutative ring spectra $k$.
Remark 3. It is subtle to extend to stacks.
Example 4. Let $\operatorname{KU}$ be the complex $K$-theory. Then $$\operatorname{KU}^{\ast}(BS^{1})=\mathbb{Z}[\![x-1]\!][\beta^{\pm}],$$ where $BS^{1}\cong \mathbb{CP}^{\infty}$ and $\beta$ is Betti class in $\operatorname{KU}^{-2}$, $x$ is the class of $\mathscr{O}(-1)$.
$$\pi_ {\ast}(KU_ {S^{1}})\cong \mathbb{Z}[x^{\pm}][\beta^{\pm}],$$ where the left hand side is equivariant $\mathbb{C}$-K-theory.
Theorem 5 (Atiyah-Segal). $\operatorname{KU}_ {G}(X)\rightarrow \operatorname{KU}(X_ {h,G})$ is a completion.
Deep insight à la Quillen, Morava,…
Let $k$ be a commutative ring spectra such that $\pi_ {\ast}C^{\ast}(BS^{1},k)\cong \pi_ {\ast}(k)[t]^{\wedge}$ by complex oriented.
The group law $\otimes: BS^{1}\times BS^{1}\rightarrow BS^{1}$ corresponds to $\pi_ {\ast}(k)[t]^{\wedge}\rightarrow \pi_ {2}(k)[t_ {1},t_ {2}]^{\wedge}$ sending $t=c_ {1}^{k}(\mathscr{L})\mapsto F(t_ {1},t_ {2})=c_ {1}^{k}(\mathscr{L}_ {1}\otimes \mathscr{L_ {2}})$.
Then $F$ is a 1-dimensional formal group law.
Example 6. If $k=\mathbb{Z}$, $F(x,y)=x+y$.
Example 7. If $k=\operatorname{KU}$, $c_ {1}(\mathscr{L})=[\mathscr{L}]-1$, $F(x,y)=x+y+xy$ (and $t=\frac{x-1}{\beta}$).
Now let $k$ be a $\mathbb{C}$-oriented commutative ring spectra and $G=T$ a torus.
Then $\operatorname{Shv}_ {T}(\operatorname{Gr}_ {T},k)\cong \oplus_ {\mathbb{X}_ {\ast}(T)}\operatorname{Shv}_ {T}(\text{pt},k)\cong \oplus_ {\mathbb{X}_ {\ast}(T)}\operatorname{Mod}(k_ {T})$, where $k_ {T}$ is either Borel $C^{\ast}(BT,k)$ or “genuine” $T$-equivariant version of $k$.
Take homotopy groups of $k_ {T}$: Given a spectra $A$, get a filtered complex $\tau_ {\geq\ast}A$ (or cohomology notation $\tau^{\leq -\ast}A$). Taking graded and shear, one gets $\pi_ {\ast}A$ ($\cong H_ {\ast}(A)$ since $A$ is a spectra).
So $k_ {T}$ is a 1 parameter degeneration (i.e. $\tau_ {\geq \ast} k_ {T}$) of $\pi_ {\ast}(k_ {T})$.
Then one get $\operatorname{Shv}_ {T}(\operatorname{Gr}_ {T},k)$ a 1-parameter degeneration of $\oplus_ {\mathbb{X}_ {\ast}(T)}\operatorname{Mod}^{\text{gr}}(\pi_ {\ast}(k_ {T})).$ If $\mathbb{H}=\operatorname{Spec}(k_ {S^{1}})$ (or $\operatorname{Spf}$), 1-dimensional (formal) group over $\pi_ {\ast}(k)$, then
$$\operatorname{Spec} \pi_ {\ast}(k_ {T}) = \operatorname{Hom}(\mathbb{X}^{\ast}(T), \mathbb{H}) =: T_ {\mathbb{H}},$$ and $$\operatorname{QCoh}(T_ {\mathbb{H}}\times B\check{T}_ {\pi_ {\ast}k})\cong \oplus_ {\mathbb{X}^{\ast}(T)}\operatorname{QCoh}^{\text{gr}}(T_ {\mathbb{H}}).$$
Summary:
We have a 1-parameter degeneration $\operatorname{Shv}_ {T(\mathbb{O})}(\mathrm{Gr}_ {T},k)$ to $\operatorname{QCoh}^{\text{gr}}(T_ {\mathbb{H}}\times B\check{T})$ from a $k$-linear category to graded $\pi_ {\ast}k$-linear category.
How to replace $T_ {\mathbb{H}}$ in general?
Definition 8. Let $\mathbb{H}$ be a 1-dimensional (formal) group scheme over $\pi_ {\ast}k$. Let $X$ be a stack over $\pi_ {\ast}k$. We define $\mathbb{H}$-loop space $L_ {\mathbb{H}}X:=\operatorname{Fun}_ {\pi(k)}^{\otimes,L}(\operatorname{QCoh}(X)^{\otimes},\operatorname{IndCoh}_ {0}(\mathbb{H})^{\text{conv}})$, where the subscript $0$ means with 0-dimensional support (or torsion sheaves) and conv stands for convolution.
Example 9. For $\mathbb{H}=\mathbb{G}_ {a}$, $L_ {\mathbb{H}}X = T[1] (X)$.
Example 10. For $\mathbb{H}=\mathbb{G}_ {m}$, then $L_ {\mathbb{H}}X = X\times_ {X\times_ {\pi_ {\ast}k}X}X$.
Definition 11. We define $G_ {\mathbb{H}}$ to be the fiber product
Example 12. Let $\mathbb{H}=\mathbb{G}_ {a}$ (or $\hat{\mathbb{G}_ {a}}$), and then $G_ {\mathbb{H}}=\mathfrak{g}$ (or $\mathfrak{g}^{\wedge}_ {\mathcal{N}}$ respectively).
Example 13. Let $\mathbb{H}=\mathbb{G}_ {m}$ (or $\hat{\mathbb{G}_ {m}}$), and then $G_ {\mathbb{H}}=G$ (or $G^{\wedge}_ {\mathcal{\mathcal{U}}}$ respectively).
Example 14. Let $\mathbb{H}=E$ be an elliptic curve and $G$ semi-simple, and then $G_ {\mathbb{H}}=\operatorname{Bun}_ {G}^{(\operatorname{SS},0)}(E)^{\text{trivial basepoint}}$ no group structure.
Conjecture 15. Let $k$ be a $\mathbb{C}$-oriented commutative ring spectra and $G$ a simply-laced simply-conencted reductive group. Then $\operatorname{Shv}_ {G(\mathbb{O})}(\mathrm{Gr}_ {G},k)$ has a one-parameter degeneration to $\operatorname{QCoh}^{\text{gr}}(G_ {\mathbb{H}}/\check{G})$ from $k$-linear category to $\pi_ {\ast}k$-linear category.
Example 16. Take $k=\mathbb{Z}$, there is a one-parameter degneration from $\operatorname{Shv}_ {G(\mathbb{O})}(\mathrm{Gr}_ {G},\mathbb{Z})$ to $\operatorname{QCoh}^{\text{gr}}(\mathfrak{g}(2)/\check{G})$, and renormalized on the left hand side corresponds to formal completion at $\mathcal{N}$ on the right hand side, i.e. there is a category over $\mathbb{A}^{1}/\mathbb{G}_ {m}$, with generic fiber being the left hand side and special fiber a category being the right hand side. Tensor over $\mathbb{Q}$, somehow it splits and recovers original derived Satake (for simply laced and simply connected $G$).
Example 17. Take $k=KU$, should get a degenreation to $\operatorname{QCoh}(G/\check{G})$ ($\operatorname{QCoh}(G_ {\mathcal{U}}^{\wedge}/\check{G})$ for renormalized version).
Theorem 18. This is true if $G\neq E_ {8}$, $k=\mathbb{Z},\operatorname{KU},$ and elliptic cohomology, and base change the categories to an algebraically closed field of large enough characteristic.
What is loop rotation in this generalized coefficients situation?
Classically, there eixsts an object $\check{R}\in \operatorname{Shv}_ {G(\mathbb{O})\rtimes \mathbb{G}_ {m}^{\text{rot}}}(\operatorname{Gr}_ {G},\mathbb{Q})$ and a $\delta$-sheaf at the base point, such that $$\operatorname{Ext}^{\bullet}_ {\operatorname{Shv}}(\delta,\check{R})\cong \mathrm{U}_ {\hbar}(\check{\mathfrak{g}}).$$
Expectation: THere eixsts $\check{R}_ {k}\in \operatorname{Shv}_ {G(\mathbb{O})\rtimes \mathbb{G}_ {m}^{\text{rot}}}(\operatorname{Gr}_ {G},k)$ and $\delta$, with $$\pi_ {\ast}R\operatorname{Hom}_ {\operatorname{Shv}}(\delta,\check{R}_ {k})=:\mathscr{A}$$ and we expect $\mathscr{A}$ to sit inside an algebra.
For $\operatorname{SL}_ {2}$, $$\mathrm{U}_ {\mathbb{H}}(\operatorname{SL}_ {2}) = \frac{\pi_ {\ast}k[t]^{\wedge}\langle e,f,h \rangle}{fh=(h+_ {F}t)f, eh=(h-_ {F}t)e, [e,f]=h(t-_ {F}h)-\overline{h}(h+_ {F}t)},$$ where $\pi_ {\ast}k[t]^{\wedge} = \pi_ {\ast}C^{\ast}(BS^{1},k)$, and $\overline{h}$=inverse of $h$ in $F$.
Warning 19. Need more verification.
Example 20. For $\mathbb{H}=\mathbb{G}_ {m}$, $\mathrm{U}_ {\mathbb{H}}(\operatorname{SL}_ {2})$ is basically $U_ {q}(\operatorname{SL}_ {2})$, and $\mathscr{A}\hookrightarrow \mathrm{U}_ {q}(\operatorname{SL}_ {2})$ corresponding to $G^{0}\hookrightarrow G$.